Capturing all Links in a page, filtering and visiting filtered pages.

Purpose: Capturing all Links in a page, filtering and visiting filtered pages.


In general while testing any application we are facing a situation where we need to visit specific link available on the Web Page. The Following script help floks how to handle it.

In the following example, I am going to visit 'www.google.com', captures all the links available on the page, filter the required link and visit that link page.

import java.util.List;
import org.openqa.selenium.By;
import org.openqa.selenium.WebDriver;
import org.openqa.selenium.WebElement;
import org.openqa.selenium.firefox.FirefoxDriver;

public class Links {
 public static void main(String[] args) throws InterruptedException {

  WebDriver driver = new FirefoxDriver();
  driver.get("http://www.tata.com/");
  driver.manage().window().maximize();
//  Extract all links from the webpage using selenium webdriver
  List<WebElement> all_links_webpage = driver.findElements(By.tagName("a"));

//  Print total no of links on the webpage
  System.out.println("Print total no of links on the webpage---------------------------------------------");
  System.out.println(all_links_webpage.size());

//  Filter the Link and visit that link
  System.out.println("Print Links------------------------------------------------------------------------");
  for(int i=0;i<all_links_webpage.size();i++)
  {
   Thread.sleep(1000);
   if(all_links_webpage.get(i).getText().toLowerCase().contains("contact"))
   {
    System.out.println("Search Resutl found");
   String link = all_links_webpage.get(i).getAttribute("href");
   driver.navigate().to(link);
   Thread.sleep(3000);
   break;
   }
  }
 driver.quit();
 }
}

Capturing all Links on a Web Page and visiting those links using Web Driver

Purpose: Capturing all Links on a Web Page and visiting those links

In general while testing any application we are facing a situation where we need to visit each link available on the Web Page. The Following script help floks how to handle it.

In the following example, I am going to visit 'www.google.com', captures all the links available on the page, visiting each link and coming back to home page.

importjava.util.List;

importorg.openqa.selenium.By;

importorg.openqa.selenium.WebDriver;

importorg.openqa.selenium.WebElement;

importorg.openqa.selenium.firefox.FirefoxDriver;

public class Links {

private static String homeWindow = null;

private static String[] links = null;

private static int linksCount = 0;

public static void main(String[] args) throws InterruptedException {

WebDriver driver = new FirefoxDriver();

driver.get("http://www.google.com/");

// Fllowing instruction extract all links from the webpage using selenium webdriver

List<WebElement> all_links_webpage = driver.findElements(By.tagName("a"));

// Print total no of links on the webpage

System.out.println("Print total no of links on the webpage----------------------------------------------------");

linksCount = all_links_webpage.size();
System.out.println(linksCount);

links= new String[linksCount];// Following instruction stores each link and Prints on console

System.out.println("Print Links-----------------------------------------------------------------------------------");

for(int i=0;i<linksCount;i++)

{

links[i] = all_links_webpage.get(i).getAttribute("href");

System.out.println(all_links_webpage.get(i).getAttribute("href"));

}

// Following instruction Return an opaque handle to this window that uniquely identifies it within this driver instance.

// This can be used to switch to this window at a later date

homeWindow = driver.getWindowHandle().toString();

// Visiting Each Link in on the Page

System.

out.println("Visiting Each Links------------------------------------------------------------------------");

for(int i=0;i<linksCount;i++)

{

driver.navigate().to(

links[i]);

Thread.sleep(3000);

driver.switchTo().window(

homeWindow);

}

driver.quit();

}

}